Question

suppose h(t)=-0.2t^2+2t models the height, in feet of a ball that is kicked into the air where as t is given time in seconds. after how many seconds does the ball reach maximum height. what is the maximum height of the ball after how many seconds does the ball reach the ground

Answer 1

Answer:

Step-by-step explanation:

h=vt-16t²+s

t= -b/2a

t= -2/.4

t=5 seconds

h= -0.2(5)²+2(5)

h= -0.2(25)+10

h= -5+10

h= 5ft

It takes 5 sec. to reach its max height so it will take 5 sec. to hit the ground so 5+5=10 10 sec. total.