A body X moves with an initial velocity of 10 m/s and acceleration 2 m/s^2. Simultaneously, another body starting from rest and moves with acceleration 3 m/s^2. X and Y will have the same velocity after an interval of time :

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Answer:

10s

Explanation:

Body X

  • Let's derive an equation for the final velocity of X
  • v = u + at
  • v = 10 + 2t [Equation 1]

Body Y

  • Similarily, we need an equation for v here as well
  • v = u + at
  • v = 0 + 3t
  • v = 3t [Equation 2]

Equating both equations

  • 10 + 2t = 3t
  • t = 10s

Apply first equation of kinematics v=u+at

For x

  • v=10+2t

For y

  • v=0+3t

So

  • x=y
  • 10+2t=3t+0
  • t=10s
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