Question

What is the solution of log(3x+4)^125 = 3? (3x+4) is the base. 125 is the argument.

x=1/3
x=1
x=7/3
x=4

Answer 1

Answer:

x = 1/3

Step-by-step explanation:

$= > log_{(3x + 4)}125 = 3$

$= > {(3x + 4)}^{3} = 125 \: ( \because \: log_{a}b = x = > {a}^{x} = b)$

$= > 3x + 4 = \sqrt[3]{125} = 5$

$= > 3x = 5 - 4 = 1$

$\therefore \: \: x = \frac{1}{3}$

Hope you've understood the solution.