Question

PLS HELP
Find the distance between the two points.
(1,1)
√ [?]
Enter the number that
goes beneath the
radical symbol.
(3,-4)

Answer 1

Answer:

The number inside radical is 29

Step-by-step explanation:

Given:

• Points (1,1) & (3,-4)

To find:

• Distance between two points

Distance Formula:

$\displaystyle \large{\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}}$

Determine (x2,y2) = (1,1) and (x1,y1) = (3,-4). Therefore:

$\displaystyle \large{\sqrt{(1-3)^2+(1-(-4))^2}}\\\displaystyle \large{\sqrt{(-2)^2+(1+4)^2}}\\\displaystyle \large{\sqrt{4+5^2}}\\\displaystyle \large{\sqrt{4+25}}\\\displaystyle \large{\therefore \sqrt{29}}$

Therefore, the number inside the radical is 29

Answer 2

Answer:

$\sqrt{29}$

Step-by-step explanation:

Hi there!

We are given the points (1, 1) and (3, -4)

We want to find the distance between the points

Distance can be found using the formula $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$, where $(x_1, y_1)$ and $(x_2, y_2)$ are points

We can label the values of the points first, before calculating to help avoid confusion and mistakes.

$x_1 = 1\\y_1 = 1\\x_2 = 3 \\y_2 = -4$

Now substitute these values into the formula

d = $\sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}$

d = $\sqrt{(3-1)^2 + (-4-1)^2}$

Now, using order of operations, first simplify what is in the parentheses:

d = $\sqrt{(2)^2 + (-5)^2}$

Now raise 2 and -5 to the second power.

d = $\sqrt{4 + 25}$

Add the numbers together under the radical

d = $\sqrt{29}$

The distance is $\sqrt{29}$

Hope this helps!

See more on finding the distance here: https://brainly.com/question/24774555