Evaluate
[tex]\dfrac{f(5)+g(1)}{f(6)-g(-2)}[/tex]
where [tex]f(x)=x-4[/tex] and [tex]g(x)=3x+6[/tex]
f(5) = 5 - 4 = 1
g(1) = 3 * 1 + 6 = 3 + 6 = 9
f(6) = 6 - 4 = 2
g(-2) = 3 * (-2) + 6 = -6 + 6 = 0
So,
[tex]\dfrac{f(5)+g(1)}{f(6)-g(-2)}\\\\\\ =\dfrac{1+9}{2-0}\\\\\\ =\dfrac{10}{2}[/tex]
[tex]=5\quad\longleftarrow\quad\textsf{this is the answer.}[/tex]
I hope this helps. =)