Question

X 0 1 2 3 4
Y 2 1 0 -1 -2
Find the inner slope

Answer 1

$\begin{array}{|c|ccccc|} \cline{1-6} x&0&1&2&3&4\\ \cline{1-6} y&2&1&0&-1&-2\\ \cline{1-6} \end{array}$

to get the slope of any straight line, we simply need two points off of it, hmm from the table let's use hmmm (2 , 0) and (4 , -2)

$(\stackrel{x_1}{2}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{4}~,~\stackrel{y_2}{-2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-2}-\stackrel{y1}{0}}}{\underset{run} {\underset{x_2}{4}-\underset{x_1}{2}}}\implies \cfrac{-2}{2}\implies -1$

Answer 2

Step-by-step explanation:

To find the slope, take 2 points from the graph. I'm going to pick (0,2) and (1,1). Whenever we find the slope this way, we need to keep this formula in mind:

$\frac{y2 - y1}{x2 - x1} = slope$

So, in this case, we need to do this:

$\frac{1 - 2}{1 - 0} = \frac{ - 1}{1}$

So the answer is -1.

If you need any further explanations, let me know!