Using the arrangements formula, it is found that 6 different orders of top-three finishers are possible.
The number of possible arrangements of n elements is given by the factorial of n, that is:
[tex]A_n = n![/tex]
In this problem, the possible orders are arrangements of 3 elements, hence, the number of orders is given by:
[tex]A_3 = 3! = 6[/tex]
More can be learned about the arrangements formula at https://brainly.com/question/25925367
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