Question

94 POINTS!!!!!! EASY STATS QUESTION. SHOW WORK
A jar contains 4 marbles - 3 Red & 1 Blue. Two marbles are drawn with replacement after each draw. What is the probability that the same color marble is drawn twice?

Answer 1

Answer: hii :)

5/8

Step-by-step explanation:

The probability of a red marble being drawn in both turns = 9/16, and the probability of a white marble being drawn in both turns = 1/16. So, the total probability = (9/16) + (1/16) = 10/16 = 5/8.

Hopefully this helps you

- Matthew

Answer 2

Answer:

$\sf \dfrac58$

Step-by-step explanation:

Given:

• 3 red marbles
• 1 blue marbles
• Total marbles = 4

$\sf Probability\:of\:an\:event\:occurring = \dfrac{Number\:of\:ways\:it\:can\:occur}{Total\:number\:of\:possible\:outcomes}$

$\implies \sf \textsf{P(red marble)}=\dfrac{3}{4}$

$\implies \sf \textsf{P(blue marble)}=\dfrac{1}{4}$

As the marbles are replaced:

$\implies \sf \textsf{P(red marble) and P(red marble)}=\dfrac{3}{4} \times \dfrac{3}{4}=\dfrac{9}{16}$

$\implies \sf \textsf{P(blue marble) and P(blue marble)}=\dfrac{1}{4} \times \dfrac{1}{4}=\dfrac{1}{16}$

Therefore:

$\implies \sf \textsf{P(red and red) or P(blue and blue)}=\dfrac{9}{16}+\dfrac{1}{16}=\dfrac{10}{16}=\dfrac58$