Question

helppppp pleaseeeeeee.

Answer 1

The area of the figure which consist the two semicircles and one rectangle with 4×8 ft dimensions is 44.6 ft².

What is the area of a rectangle?

Area of a rectangle is the product of the length of the rectangle and the width of the rectangle. It can be given as,

A=a\times b

Here, (a)is the length of rectangle and (b) is the width of the rectangle

The given figure is in two parts. It is made with 2 semicircles and 1 rectangle. The length of the rectangle part is 8 ft and width of it is 4 ft long. Thus, the area of this part is,

$A_r=8\times4\\A_r=32\rm\; ft^2$

There are two semicircles, which make one complete circle. Thus, the area of this two semicircle with radius 2 ft, is,

$A_c=\pi \times2^2\\A_c=12.57\rm\; ft^2$

Thus, the area of this composite figure is,

$A=A_r+A_c\\A=32+12.57\\A=44.57\rm\; ft^2\\A=44.6\rm\;ft^2$

Thus, the area of the figure which consist the two semicircles and one rectangle with 4×8 ft dimensions is 44.6 ft².

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