Question

4. If I have 7.7 moles of gas at a pressure of 0.090 atm and at a temperature of 56 °C, what is the volume of the container that the
gas is in?

Answer 1

Answer:

$2.31*10^3 L$ of gas are in the container.

Explanation:

1. First, convert temperature to kelvins. Otherwise, you will get the wrong answer. T = 56 + 273.15 = 329.15 K.

2.Use the ideal gas law. $PV = nRT$

3.Re-arrange for volume and use the gas contstant R = $\frac{0.082(L*atm)}{K*mol}$

4.Insert values. $PV = nRT = \frac{(7.7 moles)(0.082 L*atm/(K*mol))(329.15K)}{(0.090 atm)} = 2.31*10^3 L.$