The number of molecules of CO₂ produced from 62.4 g of C₁₀H₁₈ is equal to 27.099×10²³.
Avogadro's number is define as the number of entities present in one mole of any susbtance and it willl be equal to 6.022×10²³.
Moles (n) from mass will be calculated as:
n = W/M, where
W = given mass
M = molar mass
Given chemical reaction will be represented as:
C₁₀H₁₈ + 29/2O₂ → 10CO₂ + 9H₂O
Moles of C₁₀H₁₈ = 62.4g / 138.25g/mol = 0.45 moles
From the stoichiometry of the reaction,
0.45 mole of C₁₀H₁₈ = produces 10×0.45 = 4.5 moles of CO₂
By using the avogadro's formula, molecules of CO₂ will be calculated as:
Molecules of CO₂ in 4.5mol = 4.5 × (6.022×10²³) = 27.099×10²³
Hence required molecules of CO₂ is 27.099×10²³.
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