Question

A Ferris wheel has a radius of 80 feet. Two particular cars are located such that the central angle between them is 165º. To the nearest tenth, what is the length of the intercepted arc between those two cars on the Ferris wheel?

Answer 1

Answer: 230.4 feet

Step-by-step explanation:

arc length = circumfrance x fraction of a circle

                 = $2\pi r$ x $\frac{165}{360}$

                 = $\frac{2*\pi *80*165 }{360}$

                 = 230.4 feet to nearest tenth

Answer 2

The length of the intercepted arc between those two cars on the Ferris wheel is 230.4 feet. This is obtained by using the arc length formula in degrees.

Arc length:

The distance across the curved length is said to be arc length.

The arc length is calculated by using the formula:

arc length = circumference × fraction of circle

⇒ arc length = 2πr × θ/360° when θ is given in degrees

where r is the radius.

Given data:

Given that,

A Ferris wheel has a radius of r=80 feet

Two particular cars are located such that the central angle between them is 165° i.e., θ = 165°

Calculating the length of the arc:

arc length = 2πr × θ/360°

⇒ 2π×80×$\frac{165}{360}$

⇒ 230.38 feet

Rounding off to the nearest tenth, we get arc length = 230.4 feet.

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