Question

A –0.06 c charge is placed is in a uniform electric field with a strength of 200 n/c. what is the magnitude and direction of the force on the charge? 12 n in the opposite direction of the field 12 n in the same direction of the field 3333 n up in the opposite direction of the field 3333 n in the same direction of the field

Answer 1

The magnitude of the charge is 12 N  in the opposite direction of the field.

What is Electric field?

The term electric field refers to the region in space where the effect of a charge is felt. In this case, we are told that the magnitude of the charge is  –0.06 C.

Hence;

E = F/q

F = Eq

F = –0.06 C * 200 N/C

F = 12 N

Hence, the magnitude of the charge is 12 N  in the opposite direction of the field.

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