Question

A sample of iron (fe) with a mass of 200.0 g releases 9,840 cal when it freezes at its freezing point. what is the molar heat of fusion for iron? use q equals n delta h.. 2,747.7 cal/mol 2,771.8 cal/mol 2,811.7 cal/mol 3,280.0 cal/mol

Answer 1

The molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.

How to calculate molar heat of fusion?

The heat of fusion of a substance can be calculated by using the following formula:

Q = m∆H

Where:

• Q = quantity of heat
• m = mass
• ∆H = change in temperature of fusion

However, the quantity of heat has been given as 9840calories. The molar heat of fusion of iron can be calculated by dividing the heat of fusion by the number of moles of iron.

Moles of iron = mass ÷ molar mass

moles = 200g ÷ 55.8g/mol

moles = 3.58moles

molar heat of fusion = 9840 cal ÷ 3.58mol

molar heat of fusion = 2748.6 cal/mol

Therefore, the molar heat of fusion for iron with a mass of 200.0g releases 9,840 cal when it freezes at its freezing point is 2,747.7 cal/mol.

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Answer 2

Answer:

A) 2,747.7 cal/mol

Explanation:

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