In seals, the gene for the length of the whiskers has two alleles. The dominant allele (A) codes long whiskers and the recessive allele (a) codes for short whiskers. What percentage of offspring would be expected to have short whiskers from the cross of two long whiskered seals, one that is homozygous dominant and one that is heterozygous?
This is a punter square problem

The percentage of offspring that would be expected to have short whiskers from the cross of two long whiskered seals, one is homozygous dominant and another is heterozygous is 0% (Zero percent).

What is a Gene?

A Gene may be defined as the stretch of DNA that encodes genetic information. It may also be characterized as the sequence of nucleotides that can produce a functional protein or enzyme.

The homozygous dominant long whiskers (AA) crossed with the heterozygous long whiskers (Aa) and produce the offspring with the genotypes AA, AA, Aa, and Aa. The phenotypes of all remain the same and that is Long whiskers.

The Punnett square of the above cross is mentioned below:

Therefore, the percentage of short whiskers from this cross is 0%.

To learn more about Punnett square, refer to the link:

https://brainly.com/question/3522181

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