solve work by using square root method

[tex]~~~~(x-2)^2 = 16\\\\\implies x-2 = \pm\sqrt{16}\\\\\implies x-2 = \pm4\\\\\implies x= \pm4 +2\\\\\implies x=-4+2~~ \text{or}~~ 4+2\\\\\implies x = -2~~ \text{or}~~ 6[/tex]
Answer:
[tex]x = - 2[/tex]
[tex]x = 6[/tex]
Step-by-step explanation:
[tex](x - 2)^{2} = 16[/tex]
[tex]x - 2 = ± \: 4[/tex]
[tex]x - 2 = - 4[/tex]
[tex]x - 2 = 4[/tex]
[tex]x = - 2[/tex]
[tex]x = 6[/tex]