Question

How many milliliters of an aqueous solution of 0.210 M calcium acetate is needed to obtain 13.4 grams of the salt?

Answer 1

Explanation:

0,147 mol of CuBr2 equil  224 g/mol x 0.147 mol =33 gram

In 1 L solution dissolved 33 g of salt, but we want to get 13.9 g of salt

therefore, 13.9 g will be in the  aqueous solution of volume  0.42 L or 420 mL

( 13.9 / 33 = 0.42 L)