Respuesta :
P(A or B) = P(A) + P(B) - P(A and B)
P(A or B)=0.7+0.55-0.3
P(A or B)= 0.4+0.55
P(A or B)=0.95
Answer:
[tex]\frac{19}{20}[/tex]
Step-by-step explanation:
Let T represents the event of phones with a touch screen and H represents the event of phones with HD movie capability.
Given,
70% of the phones with a touch screen,
⇒ The probability of touch screen phone, P(T) = 70% = 0.7,
55% of the phones with HD movie capability,
⇒ The probability of HD movie capability phones, P(H) = 55 % = 5.5,
Also, 30% of the phones have both a touch screen and HD movie capability,
⇒ The probability of HD movie capability phones with touch screen,
P(H∩T) = 30 % = 0.3,
Hence, the probability that a smartphone chosen at random has either a touch screen or HD movie capability is,
[tex]P(H\cup T)= P(H)+P(T)-P(H\cap T)[/tex]
[tex]=0.7+0.55 - 0.3[/tex]
[tex]=0.95[/tex]
[tex]=\frac{95}{100}[/tex]
[tex]=\frac{19}{20}[/tex]
First option is correct.