Question

Help solving this problem

Answer 1

Answer:

A=0.50

B=0.477

C=0.423<p<0.531

Step-by-step explanation:

sample size N :333

number of success X: 159

sample part of success x/n = 159/333

x=0.477 B

0.50 A Half a chance to flip a tail or head

part C:

$0.477 plusminus 1.96 * \sqrt{ \frac{0.477 (1 - 0.477)}{333} }$

simplify

$0.477 plusminus 1.96 * 0.0536$

expand

$0.477 + 1.96 * 0.0536$

$0.531$

expand minus

$0.477 - 1.96 * 0.0536$

$0.423$

finally answer part c

$0.423 < p < 0.531$