Answer:
2: 142.5
3: 42
Step-by-step explanation:
Remark
Problem 2
The diagonals of a kite meet at right angles. They also bisect each other. So the two triangles on the left and right side of the kite are congruent.
Because the smaller diagonal is bisected, you need only find the area of 1 of the triangles and double it.
1/2 of the smaller diagonal is the altitude of the triangle. The base is the other larger diagonal.
Solution
Area of the left triangle
Givens
altitude = 7.5
Base = 14 + 5 = 19
formula
Area = 1/2 * B * h
Solution
Area = 1/2 * 19 * 7.5
Area = 71.25
But there are 2 such triangles
Area of both = 71.25 * 2 = 142.5
Answer: A
Problem 3
Remark
The way they have given you the problem, you could be easily fooled. The 2 does not help you at all.
A parallelogram has an area of B * h. Those are the two numbers you use.
Givens
Base = 6
height = 7
Formula
Area = B * h
Solution
Area = 6*7
Area = 42
Answer: Area = 42m^2
