Respuesta :

Given:

In Δ[tex]WXY,m < Y=90^o,WY=3,XW=5[/tex] and [tex]YX=4[/tex].

To find:

The ratio represents the cosine of ∠[tex]W[/tex].

Solution:

In Δ[tex]WXY,m < Y=90^o[/tex]. It means the opposite side of angle Y, i.e., XW is the hypotenuse of the triangle.

In a right angle triangle,

[tex]cos0=\frac{Base}{Hypotenuse}[/tex]

In the given triangle,

[tex]cosW=\frac{XY}{YW}[/tex]

[tex]cosW=\frac{3}{5}[/tex]

Therefore, the required cosine ratio is [tex]\frac{3}{5}[/tex].

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