Given:
In Δ[tex]WXY,m < Y=90^o,WY=3,XW=5[/tex] and [tex]YX=4[/tex].
To find:
The ratio represents the cosine of ∠[tex]W[/tex].
Solution:
In Δ[tex]WXY,m < Y=90^o[/tex]. It means the opposite side of angle Y, i.e., XW is the hypotenuse of the triangle.
In a right angle triangle,
[tex]cos0=\frac{Base}{Hypotenuse}[/tex]
In the given triangle,
[tex]cosW=\frac{XY}{YW}[/tex]
[tex]cosW=\frac{3}{5}[/tex]
Therefore, the required cosine ratio is [tex]\frac{3}{5}[/tex].