1.Solve for x: 4 over x plus 4 over quantity x squared minus 9 equals 3 over quantity x minus 3.
(4/x) + [4/(x^2 - 9)] = 3/(x - 3)
LCD: x(x + 3)(x - 3)
4(x + 3)(x - 3) + 4x = 3(x)(x + 3)
4(x^2 - 9) + 4x = 3x^2 + 9x
4x^2 - 36 + 4x = 3x^2 + 9x
x^2 - 5x - 36 = 0
(x - 9)(x + 4) = 0
x = 9 or x = - 4
