Given Equation of Circle :-
[tex]\bull\:[/tex][tex]\sf{x^2+y^2 -10x+8y + 1= 0}[/tex]
[tex]\\[/tex]
Solution:-
The general form of circle is given by the equation by the equation -
[tex]\green{ \underline { \boxed{ \sf{x^2+y^2 + 2gx+2fy + c = 0}}}}[/tex]
in which
- coordinate of center = (-g , -f )
- radius of circle = [tex]\sqrt{g^2+f^2-c}[/tex]
❀ Comparing given equation with general form of circle -
So, Center of Circle = (-(-5), -4)
➥ (5, -4)
[tex]\\[/tex]
Also, radius of circle = [tex]\sqrt{(-5)^2+4^2-1}[/tex]
➥ [tex]\sqrt{25+16-1}[/tex]
➥ [tex]\sqrt{40}[/tex]
➥ [tex]2\sqrt{10}[/tex] units .
