Answer:
Below,
Step-by-step explanation:
(a) f is not defined when x = 2 because this would make the denominator = zero.
(i) f-1 is the inverse of f.
Let y = (x + 1)/(x - 2)
y(x - 2) = x + 1
xy - 2y = x + 1
xy - x = 2y + 1
x(y - 1) = 2y + 1
x = (2y +1)/(y - 1)
Replace x by f-1 and y by x , we get:
f-1 = (2x+ 1)(x - 1)
(ii) f-1 is not defined when x = 1 , as this makes the denominator zero.
