Question

Nine of the numbers 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 are to be put in two groups so that the sum of the numbers in each group is a multiple of four.

What is the largest number that could be left out?

Answer 1

Answer:

13,62,75,48,1092

Step-by-step explanation:

1+3=4, 6+2=8, 7+5=12, 4+8=12& 1+0+9+2=12.