Following the equation and the stoichiometry of the reaction, excess reactant.
The excess reactant has to do with that reactant that is present in more amount than is required in the reaction.
In this case, we have the reaction; 2NBr3 + 3NaOH ---> N2 + 3NaBr + 3HOBr.
If 2 moles of NBr3 reacts with 3 moles of NaOH
x moles of NBr3 reacts with 48 moles of NaOH
x = 32 moles
Hence, NBr3 is the excess reactant.
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