The equation of the hyperbola is D. [tex]y^2/16^2-x^2/12^2=1[/tex]
Given that the focus is at (0, 20)
Directrix is y= -256/20
What is the relation between a, b, and c?
[tex]a^2 +b^2 = c^2\\b^2 + (16)^2= (20)^2\\b^2= 400 -256\\b^2= 144[/tex]
b= 12
Making use of the vertices, foci, asymptotes, directrices, and standard equation, we find the equation of the hyperbola is [tex]y^2/16^2-x^2/12^2=1[/tex]
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