Question

What is the mole fraction of Ca3(PO4)2 by dissolving 126.32 g of calcium phosphate, Ca3(PO4)2, in 850 grams of H2O?

Answer 1

Based on the total moles of substance in the solution, the mole fraction of Ca3(PO4)2 is 0.0086

What is mole fraction?

Mole fraction is the fractions of the moles of a substance present in a given total moles of a mixture.

• The mole fraction = moles of substance/total moles of mixture

Moles of Ca3(PO4)2 is calculated first:

Moles of Ca3(PO4)2 = mass/molar mass

molar mass of Ca3(PO4)2 = 310 g

Moles of Ca3(PO4)2 = 126.32/310 = 0.41

Moles of water = 850/18 = 47.22

Total moles = 47.63

Mole fraction of Ca3(PO4)2 = 0.41/47.22 = 0.0086

Therefore, the mole fraction of Ca3(PO4)2 is 0.0086

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