Explanation:
Let N be normal
Let n be for color blindness
A carrier gene would be Nn and the colour blind guy would be nn
Parental Phenotype: Carrier × Colour Blind
Parental Genotype: Nn × nn
Random Fertilization: *show box diagram*
Offspring Genotype : Nn, Nn, nn, nn.
Offspring Phenotype: Carrier, Carrier, CB, CB.
Probability that the child would be colour blind is 2:4 which is 1/2 or 50% or 0.5 chance.