Find the center of the circle given by this equation:

Answer:
center of the circle is (5, -3) and radius of the circle is 8 units
Step-by-step explanation:
Find the center of the circle given by this equation:
x²-10x+y²+6y-30=0
for x
b= -10
for y
b=+6
complete the square
for x
(-10/2)² = 25
for y
(6/2)²=9
x²-10x+25
y²+6y+9
(x²-10x+25)+(y²+6y+9)+30=0+25+9
(x²-10x+25)+(y²+6y+9)=25+9+30
(x-5)²+(y+3)²=64
This is the form of a circle. Use this form to determine the center and radius of the circle
(x − h)² + (y − k)² = r²
Circle Equation
(x-a)² + (y−b) ² = r² is the circle equation with a radius r, centered at (a, b)
Rewrite x² - 10x + y² + 6y - 30 = 0 in the form of the standard circle equation
(x − h)² + (y − k)² = r²
(x - 5)² + (y-(-3))² = 8²
(x-5)² + (y+3)² = 8²
r=8
h=5
k=-3
signs of h and k are opposite of what they are inside the parenthesis
Match the values in this circle to those of the standard form. The variable r represents the radius of the circle, h represents the x- offset from the origin, and k represents the y-offset from origin.
r=8
h=5
k=-3
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Brian McLogan
Alex Federspiel