Answer:
First: -1628
Second: -16
Step-by-step explanation:
For the first problem, start by rewriting the equation by plugging in h and g as (4n-3)(-4n-4)
By FOILing this, you’ll end up with -16n^2-16n+12n+12
-16n^2-4n+12
Now you can plug in n, which is -10:
-16(10)^2-4(10)+12
-1600-40+12
-1628
For the second question, you’ll be plugging f(-2) into g, but I’ll leave -2 as n for simplicity until the end
g(n)=n^2+2n
f(n)=2n-4
g(n)=(f(n))^2+2(f(n))
(2n-4)^2+2(2n-4)
(4n^2-16n+16) + (4n-8)
4(-2)^2-16(-2)+16+4(-2)-8
16-32+16-8-8
-16
