Question

The length breadth and height of a sectangular box are 24 cm, 6 cm and 2cm respectevely. Find the area of largest surface of box?​

Answer 1

Answer:

$408cmx^{2}$

Step-by-step explanation:

A=2(wl+hl+hw)=2·(2·6+24·6+24·2)= 408cm²

Answer 2

given:

length= 6

width= 2

height= 24

to find:

the area if the box.

solution:

$a = lwh$

$a = 2(wl + hl + hw)$

$a = 2 \times (2.6 + 24.6 \times + 24.2)$

$a = 408 {cm}^{2}$

therefore, the area of the box is 408 square centimeters.