Question

In a certain Algebra 2 class of 21 students, 12 of them play basketball and 14 of them play baseball. There are 5 students who play neither sport. What is the probability that a student chosen randomly from the class plays basketball or baseball?

Answer 1

The probability that a student is chosen randomly from the class plays both basketball and baseball is 4/21

Probability is the likelihood or chance that an event will occur.

• Probability = Expected outcome/Total outcome

• If the total number of people in the class is 21 students, hence the total outcome is 21

Get the number of students that plays both basketball and baseball

n(U) = n(B)only + n(Ba)only + n(BnBa) + n(BuBa)'

21 = 6-x + 14-x + x + 5

21 = 25 -x

x = 25 - 21

x = 4

Hence 4 students play both basketball and baseball

Pr(basketball and baseball) = 4/21

Hence the probability that a student chosen randomly from the class plays both basketball and baseball is 4/21

Learn more on probability here; https://brainly.com/question/13604758