Respuesta :
Answer:
Below in bold.
Step-by-step explanation:
a) we need the grestest common factor of theses values
153 = 3 * 3 * 17
255 = 3 * 5*17
357 = 3 * 7 * 17
The GCF = 3 * 17 = 51.
a) the least possible number of children is 3.
b) The maximum number is 51 ( as 51 is the GCF of the given values).
c) the least possible number of fruits is when b) occurs, that is:
153/51, 255/51 and 357/51
= 3 apples , 5 oranges and 7 pears.
d) the maximum number of fruits is :
153/3, 255/3 and 357/3
= 51 apples , 85 oranges and 119 pears.
Answer:
a) 3 children
b) 51 children
c) 3 apples, 5 oranges and 7 pears
d) 51 apples, 85 oranges and 119 pears
Step-by-step explanation:
lnc - Least possible number of children in group
mnc - maximum possible number of children in group
a - Apples
o - Oranges
p - Pears
a = 153
o = 255
p = 357
a)
To solve this, find the highest divisor for the apples, oranges and pears.
[tex]a = \frac{153}{51} [/tex]
[tex]a = 3[/tex]
[tex]o = \frac{255}{85} [/tex]
[tex]o = 3[/tex]
[tex]p = \frac{357}{119} [/tex]
[tex]p = 3[/tex]
In order for each child to get 51 apples, 85 oranges and 119 pears, there would need to be a minimum of 3 children in the group.
[tex]lnc \: = 3[/tex]
b)
To solve this, find the lowest divisor for the apples, oranges and pears.
[tex]a = \frac{153}{3} [/tex]
[tex]a = 51[/tex]
[tex]o = \frac{255}{5} [/tex]
[tex]o = 51[/tex]
[tex]p = \frac{357}{7} [/tex]
[tex]p = 51[/tex]
In order for each child to get 3 apples, 5 oranges and 7 pears, there would need to be a maximum of 51 children in the group.
[tex]mnc = 51[/tex]
c)
In a group of 51, each child will get:
- 3 apples
- 5 oranges
- 7 pears
d)
In a group of 3, each child will get
- 51 apples
- 85 oranges
- 119 pears