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(x-5)2=16


The first step you can take to solve this quadratic is to take the square root of both sides of the equation.

√[(x-5)2]=√(16)

When you take the square root of a term that is square it equals what is inside the parentheses.

So on the left side, you have x-5

On the right side, you are what we call "forcing" the square root. When this happens, you need to put ±. Why? Good question. When you square a negative number it positive; when you square a positive number it is also positive.

The √16 = ±4

So now we have;
x-5=±4

What do you do with that?
You make two separate equations.

x-5=4 and x-5=-4
x=9 x=1


Let's check our answers

x=9

(x-5)2=16
(9-5)2=16
42=16
16=16 it checks

x=1

(x-5)2=16
(1-5)2=16
(-4)2=16
16=16 it also checks


ANSWER: x=9 and x=1

[tex]~~~~~(x+5)^2 = 16\\\\\implies x+5 = \pm\sqrt{16}\\\\\implies x+5 = \pm 4\\\\\implies x =-5 \pm 4\\ \\\implies x = -9~~ \text{or}~~~x=-1[/tex]

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