The area of the rectangle whose perimeter is 24 units and one side is of 'a' units, in terms of 'a' is given as: S = a(12-a) unit²
Suppose that the two adjacent sides of a rectangle be of 'a' units and 'b' unit lengths.
Then, we get the area of that rectangle as:
[tex]S = a \times b \: \rm unit^2[/tex]
For this case, we're specfied that:
Let the other side (adjacent) be of 'b' units length
Then, as perimeter of a rectangle = 2(sum of lengths of one pair of adjacent sides of the rectangle)
Therefore, we get:
[tex]24 = 2(a+b)\\\text{Dividing both the sides by 2}\\12 = a + b\\b = 12 - a[/tex]
We expressed 'b' in terms of 'a' so that we can represent the area of the considered rectangle in terms of 'a' alone.
The area of the rectangle is:
[tex]S =a \times b = a \times (12 - a) \: \rm unit^2[/tex]
Thus, the area of the rectangle whose perimeter is 24 units and one side is of 'a' units, in terms of 'a' is given as: S = a(12-a) unit²
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