The probability of throwing a drop of paint into one of the triangles is 3.96% if a large white canvas, 9' x 21', has two triangles painted on it, one with a base of a 1' and a height of 3', and the other with a right triangle with a hypotenuse of 5' and a side of 3'
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes in other words the probability is the number that shows the happening of the event.
Total area of the canvas = 9' x 21' = 189 square units
This area is representing the total outcome = 189
Total favorable outcome = area of first triangle + area of the second
triangle
Area of the first triangle = (1/2)(1x3) = 3/2 square units
From the Pythagoras theorem:
Height = √(5² - 3²) = 4'
Area of the second triangle = (1/2)(3x4) = 6 square units
Total favourable outcome = 3/2 + 6 = 15/2
Now the probability:
[tex]= \frac{\frac{15}{2} }{189}[/tex]
= 15/378
= 0.0396×100
= 3.96%
Thus, the probability of throwing a drop of paint into one of the triangles is 3.96% if a large white canvas, 9' x 21', has two triangles painted on it, one with a base of a 1' and a height of 3', and the other with a right triangle with a hypotenuse of 5' and a side of 3'
Learn more about the probability here:
brainly.com/question/11234923
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