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A 2700 Ohm resistor and electric circuit draws a current of 2.4 Milliamperes
the total charge that passes through the resistor in 15 seconds is

Respuesta :

3.6 x 10^-2 C

I is equal to change in q over t. So, q is equal to It, We know I and t. Multiply them to get 3.6 x 10^-2

The total charge (Q) that passes through the resistor in 15 seconds is 3.6 × 10⁻² Coulombs

The total charge (Q) inside an electric circuit is the total electrical current energy stored in the circuit per the dissipated energy in one period of time.

The total charge (Q) can be expressed by using the relation:

  • Q = It

From the parameters given:

  • Q = 2.4 milliamperes × 15 seconds
  • Q = 0.0024 amperes × 15 seconds
  • Q = 3.6 × 10⁻² Coulombs

Learn more about the total charge (Q) in an electric circuit here:

https://brainly.com/question/15851252

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