Question

can someone explain how tod these math problems

Answer 1

1.  First, let's find out how big the square is:

$A_{square} = 6^{2} = 36in^{2}$

Now let's find the area of the circle:

$A_{circle} = \pi3^{2} \approx 28.27in^{2}$

Now to find what area is left after removing the circle, all you have to do is subtract!

$A_{shape} = 36-28.27 \approx 7.73in^{2}$

2.  Do the same exact thing, but instead of finding the area inside of a square and subtracting a circle, find the area of the circle and subtract a triangle.

3.  Once again, do the same thing.  Find the area of the big circle and subtract out the area of the smaller circle.