Respuesta :
d - the distance from the child to the tower;
h - the height of the tower ( h = x + 1.6 m )
The system is:
tan 30° = x / d
tan 60° = x / ( d - 20 )
-------------------------------
the 1st equation: 1 / √3 = x / d ⇒ d = x √3
the 2nd equation: √3 = x / ( d - 20 )
-------------------------------------------------
√3 = x / ( x √3 - 20 ) / · ( x√3 - 20 ) ( we will multiple both sides )
√3 ( x √3 - 20 ) = x
3 x - 20 √3 = x
3 x - x = 20 √3
2 x = 20 √3
x = 20 √3 : 2
x = 10 √ 3 ≈ 17.3 m
The height of the tower ( menara ):
h = 10 √ 3 + 1.6 m ≈ 17.3 + 1.6 ≈ 18.9 m
h - the height of the tower ( h = x + 1.6 m )
The system is:
tan 30° = x / d
tan 60° = x / ( d - 20 )
-------------------------------
the 1st equation: 1 / √3 = x / d ⇒ d = x √3
the 2nd equation: √3 = x / ( d - 20 )
-------------------------------------------------
√3 = x / ( x √3 - 20 ) / · ( x√3 - 20 ) ( we will multiple both sides )
√3 ( x √3 - 20 ) = x
3 x - 20 √3 = x
3 x - x = 20 √3
2 x = 20 √3
x = 20 √3 : 2
x = 10 √ 3 ≈ 17.3 m
The height of the tower ( menara ):
h = 10 √ 3 + 1.6 m ≈ 17.3 + 1.6 ≈ 18.9 m
The height of the tower is [tex]\boxed{18.92{\text{ m}}}.[/tex]
Further explanation:
The Pythagorean formula can be expressed as,
[tex]\boxed{{H^2} = {P^2} + {B^2}}.[/tex]
Here, H represents the hypotenuse, P represents the perpendicular and B represents the base.
The formula for tan of angle a can be expressed as
[tex]\boxed{\tan a = \frac{P}{B}}[/tex]
Explanation:
In triangle ABF,
[tex]\begin{aligned}\tan {60^ \circ }&= \frac{H}{x}\\\sqrt3&= \frac{H}{x}\\\sqrt 3 x &= H\\\end{aligned}[/tex]
In triangle ABE,
[tex]\begin{aligned}\tan{30^ \circ }&= \frac{H}{{20 + x}}\\\frac{1}{{\sqrt3 }}&= \frac{H}{{20 + x}}\\\sqrt 3 H&= 20 + x\\H&=\frac{{20 + x}}{{\sqrt 3 }}\\\end{aligned}[/tex]
Equate the value of H.
[tex]\begin{aligned}\sqrt 3 x &= \frac{{20 + x}}{{\sqrt 3 }}\\\sqrt 3 x \times \sqrt3 & = 20 + x \\3x &= 20 + x\\ 3x - x &= 20 \\ 2x &= 20\\x&=10 \\\end{aligned}[/tex]
The value of H can be obtained as follows,
[tex]\begin{aligned}H&= \sqrt3\times 10\\&= 10 \times 1.732\\&= 17.32\\\end{aligned}[/tex]
The height of the tower can be obtained as follows,
[tex]\begin{aligned}h&= H + 1.60\\&= 17.32 + 1.60 \\ &= 18.92\\\end{aligned}[/tex]
The height of the tower is [tex]\boxed{18.92{\text{ m}}}.[/tex]
Kindly refer to the image attached.
Learn more:
- Learn more about inverse of the functionhttps://brainly.com/question/1632445.
- Learn more about equation of circle brainly.com/question/1506955.
- Learn more about range and domain of the function https://brainly.com/question/3412497
Answer details:
Grade: High School
Subject: Mathematics
Chapter: Trigonometry
Keywords: tower, a child, height of 160 cm, elevation angle, 30 degree, 60 degree, he walks, far, approaching tower, elevation, height of tower.
