Question

Suppose you are pushing a stalled car. As the gets going, you need less and less force to keep it going. For the first 15 m, your force decreases at a constant rate from 210.0 N to 40.0 N. How much work did you do on the car? Draw a force-displacement graph to represent the work done during this period.���

Answer 1

Answer:

1875 j

Explanation:

f * d = work

your AVERAGE force is (210+ 40)/2 = 125 N

125 * 15 = 1875 j

Answer 2

The work done during this period will be 1875 J.. if the body is displaced in the same direction of the force it will be positive.

What is work done?

Work done is defined as the product of applied force and the distance through which the body is displaced on which the force is applied.

Work may be zero, positive and negative.it depends on the direction of the body displaced

The given data in the problem is;

F is the average force applied by the worker

d is the displacement = 15 m

The average force is ;

$\rm F_{AVG} = \frac{F_1+F_2}{2} \\\\ F_{AVG} = \frac{210+40}{2} \\\\ F_{AVG}=125 \ J$

The work done by the worker will be;

$\rm W= Fd \\\\\rm W= F_{AVG}d \\\\W= 125 \times 15 \\\\ \rm W=1875 \ J$

Hence the work done during this period will be 1875 J.

To learn more about the work done refer to the link ;

https://brainly.com/question/3902440