Question

What are the minimum number of bits an address bus must have in a byte addressable memory system containing only 4 KiB of memory

Answer 1

The minimum number of bits the address bus must have in the byte addressable memory system is 12

How to determine the minimum number of bits?

The memory size is given as;

Size = 4 KiB

Convert to bytes

Size = 4 * 2^10 bytes

Express 4 as 2^2

Size = 2^2 * 2^10 bytes

Multiply

Size = 2^12 bytes

The minimum number of bits is then calculated as;

2^n =  Size

This gives

2^n = 2^12

Cancel out the base (2)

n = 12

Hence, the minimum number of bits is 12

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