Since you detect a small photocurrent for light with wavelength up to 451 nm, the metal the electrode is made of is Sodium.
To solve the question, we need to know what work function is.
This is the minimum energy at which an electron will be emitted from the surface of a metal.
Since a small photocurrent is detected when ligh of wavelength up to 451 nm is applied with a zero potential difference applied, this is the threshold wavelength which gives the work function of the metal.
So, work function Ф = hc/λ where
Substituting the values of the variables into the equation, we have
Ф = hc/λ
Ф = 6.63 × 10⁻³⁴ Js × 3 × 10⁸ m/s ÷ 451 × 10⁻⁹ m
Ф = 19.89 × 10⁻³⁴ × 10⁸ Jm ÷ 451 × 10⁻⁹ m
Ф = 0.0441 × 10⁻¹⁷ J
Ф = 4.41 × 10⁻¹⁹ J
Since 1 eV = 1.602 10⁻¹⁹ J,
Ф = 4.41 × 10⁻¹⁹ J × 1 eV/1.602 10⁻¹⁹ J
Ф = 2.753 eV
From tables, the metal with the work function closet to this value is Sodium.
So, the metal the electrode is made of is Sodium.
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