Question

Given that the molar mass of nacl is 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of nacl in 500. ml of solution? use molarity equals startfraction moles of solute over liters of solution endfraction.. 0.333 m 0.751 m 1.50 m 3.00 m

Answer 1

The molarity of the solution that contains 87.75 g of NaCl in 500 mL of the solution is 3 M

What is molarity?

This is defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:

Molarity = mole / Volume

How to determine the mole of NaCl

• Mass of NaCl = 87.75 g of
• Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
• Mole of NaCl =?

Mole = mass / molar mass

Mole of NaCl = 87.75 / 58.5

Mole of NaCl = 1.5 mole

How to determine the molarity

• Mole of NaCl = 1.5 mole
• Volume = 500 mL = 500 / 1000 = 0.5 L
• Molarity =?

Molarity = mole / Volume

Molarity = 1.5 / 0.5

Molarity = 3 M

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Answer 2

Answer:

i think its d

Explanation:

eez nuts