Question

If $x^{1/4}= \frac{1}{p}$ and $y^{1/2}= \frac{1}{q}$ , what is the value of $\sqrt{xy}$

Answer 1

$x^{1/4}=\dfrac1p\implies x=\dfrac1{p^4}$
$y^{1/2}=\dfrac1q\implies y=\dfrac1{q^2}$

$\implies \sqrt{xy}=\sqrt{\dfrac1{p^4}\times\dfrac1{q^2}}=\dfrac1{p^2q}$