A 7.8-kg solid sphere, made of metal whose density is 2500 kg/m3, is suspended by a cord. When the sphere is immersed in water (of density 1000 kg/m3), what is the tension in the cord

Respuesta :

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force =

Where

is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

Thus, the density of the liquid = 1470.43 kg/m³

Density of the liquid = 1470.43 kg/m³

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

Volume displaced = 0.002346 m³

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

How do you find the string tension?

The tension of a given rope can be thought of as T = (m × g) + (m × a). Where "g" is the gravitational acceleration of all objects supported by the rope and "a" is the other acceleration. All objects are carried by rope.

Tension represents the force a string or chord receives when someone or something pulls it. In other words, whenever the cord is pulled, it is said to be under tension. Whenever we deal with code or code issues, we assume that the code is flexible and has no mass.

Learn more about tension in the cord here: https://brainly.com/question/14104046

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