Question

A data set includes body temperatures of healthy adult humans having a mean of f and a standard deviation of f. construct a ​% confidence interval estimate of the mean body temperature of all healthy humans. what does the sample suggest about the use of 98.6f as the mean body​ temperature?

Answer 1

What the sample suggests is that; the mean body temperature couldvery possibly bevery possibly be 98.6 °F.

What is the Confidence Interval?

For a 99% Confidence Interval and DF = 103 - 1 = 102, the value of z = 2.33.

The formula for confidence interval is;

CI = x⁻ ± z(σ/√n))

We are given;

Sample mean; x⁻ = 98.9

standard deviation; σ = 0.67

sample size; n = 103

Thus the confidence Interval is;

CI = [98.9 - 2.33(0.67/√103)], [98.9 + 2.33(0.67/√103)]

CI = (98.9 - 0.154, 98.5 + 0.154)

CI = (98.36, 98.64)

Thus, 98.6 is contained within the 99% CI,and so we can conclude that the the mean body temperature could very possibly bevery possibly be 98.6 °F.

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