For a 5.0 µC point charge moved within an electric field, the electric potential difference is mathematically given as
du=2*10^6
What is the electric potential difference before and after the charge was moved?
Generally, the equation for the change in potential energy is mathematically given as
dV=qdu
Therefore
10=5*10^{-6}*du
du=2*10^6
In conclusion, the electric potential difference
du=2*10^6
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