For a block undergoing simple harmonic oscillation, the maximum amplitude is mathematically given as
a=0.0749m
What is the maximum amplitude at which the block will stay on the platform?
Generally, the equation for the maximum acceleration is mathematically given as
Ma=A*w^2
Where
A = 0.075 m
Therefore
0.075 * w^2 = 9.8
w = 11.43 rad/s
In conclusion, maximum frequency
mF=w/2pi
mF=11.43/2pi
mF= 1.82 Hz
Where
g=2\pif)^2a
a=(9.8)/4*\pi^2(1.82)^2
a=0.0749m
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