Question

X=t+4 y=3tpower of 2 -t+5
Convert the Parametric equation

Answer 1

$\bf \begin{cases} x=t+4\to x-4=\boxed{t} \\ \quad \\ \quad \\ y=3t^2+5\to y-5=3t^2\\ \frac{y-5}{3}=t^2\to \sqrt{\frac{y-5}{3}}=\boxed{t} \end{cases}\qquad thus\quad t=t \\ \quad \\\\ \quad \\ \quad \\ x-4=\sqrt{\cfrac{y-5}{3}}\implies (x-4)^2=\cfrac{y-5}{3} \\ \quad \\ 3(x-4)^2=y-5\implies 3(x-4)^2+5=y$